If I have multiple processes and am using socket.io-redis, when I do io.to(room).emit(namespace, message); is this handled seamlessly and efficiently? Or am I misunderstanding socket.io-redis's role?
1 Answers
Answers 1
Hi in short as far as I know about this is-
io.to('room').emit('namespace', 'message'); Means, sending message named 'namespace' with value 'message' to all clients in 'room' channel, including sender.
Detail info (found in here)-
// send to current request socket client socket.emit('message', "this is a test");// Hasn't changed // sending to all clients, include sender io.sockets.emit('message', "this is a test"); // Old way, still compatible io.emit('message', 'this is a test');// New way, works only in 1.x // sending to all clients except sender socket.broadcast.emit('message', "this is a test");// Hasn't changed // sending to all clients in 'game' room(channel) except sender socket.broadcast.to('game').emit('message', 'nice game');// Hasn't changed // sending to all clients in 'game' room(channel), include sender io.sockets.in('game').emit('message', 'cool game');// Old way, DOES NOT WORK ANYMORE io.in('game').emit('message', 'cool game');// New way io.to('game').emit('message', 'cool game');// New way, "in" or "to" are the exact same: "And then simply use to or in (they are the same) when broadcasting or emitting:" from http://socket.io/docs/rooms-and-namespaces/ // sending to individual socketid, socketid is like a room io.sockets.socket(socketid).emit('message', 'for your eyes only');// Old way, DOES NOT WORK ANYMORE socket.broadcast.to(socketid).emit('message', 'for your eyes only');// New way Even more can be found here.
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