Wednesday, May 31, 2017

How to create the strings sequence into specified line in edited text?

By Hường Hana 3:30 AM vim Leave a Comment

Here is the initial text.

test1 test2

Only two lines in the text.

I want to insert strings sequence into from 5th line into 16th line. I have tried it with below codes.

for i in range(1,12)       echo ".item".i."," endfor

1.the initial text.
2.to enter into command mode and input the codes

Two problems to be solved.
1.echo command output the first string .item1 before endfor.

for i in range(1,12)       echo ".item".i.","

2.How create the strings sequence into specified line:from 5th till 16th in edited text with vimscript?

The desired result is as below.

Almost done！
What i get is as below with the command :pu! =map(range(1,12), 'printf(''item%1d'', v:val)').

Both of them can't work.

:5pu! =map(range(1,12), 'printf(''item%1d'', v:val)') :5,16pu! =map(range(1,12), 'printf(''item%1d'', v:val)')

The last issue for my desired format is when the cursor is on the 3th line ,how to create the desired output?

2 Answers

In order to insert the missing lines, without inserting unrequired empty lines (-> append() + repeat([''], nb) + possible negative nb)

:let lin = 5 - 1 :call append('$', repeat([''], lin-line('$')))

Then, in order to insert what you're looking for (no need for printf() if you don't want to format the numbers)

:call append(lin, map(range(1,12), '"item".v:val'))

PS: I'd rather avoid :put when I can as it's kind of difficult to use with complex expressions.

Assuming you are in a Unix based operating system, you have a seq command. So you can do:

$ seq -f 'Item %.0f' 20 Item 1 Item 2 ... Item 20

Inside vim you can try the reading from external command approach:

:r! seq -f 'Item \%.0f' 20